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5w^2-7w-4=0
a = 5; b = -7; c = -4;
Δ = b2-4ac
Δ = -72-4·5·(-4)
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{129}}{2*5}=\frac{7-\sqrt{129}}{10} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{129}}{2*5}=\frac{7+\sqrt{129}}{10} $
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